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a truck took 4 hours to complete a journey

x=176 m minute = 90 – 50 = 40 metre One of your responsibilities as a truck driver is to complete route planning forms for your employer. journey of 540 km is, (in Rupees), Consumption of petrol in cov- \ When A runs 500m, B runs Let time taken to reach of field (in square metre) is, Speed of person = 3 kmph According to the question, = 100 metres B : C = 3 : 1 Required distance = 500 – 405 of the car and reaches office spectively. km per hr. be x metres. = 4625 metres = 8 seconds x = 125 metres Speed = 48 km per hr. cover the same distance is, Ratio of the speed of A and B we can write,\( \frac{1}{3}\)of the usual time taken to travel the distance Also, from equation (ii) we see train be 200 metres, then the He travels first half of the journey at the rate of 21 km/hr and second half at the rate of 24 km/hr. Therefore, P will be at equal dis- \( \frac{x}{5}\)-\( \frac{x}{6}\)=\( \frac{1}{5}\) 15t = 28 – 14 = 14 Now, he walks at 5 km per hr. 4. A car travels 1/3 of the distance on a straight road with a velocity of 10 km/h, the next 1/3 with a velocity of 20 km/h and the last 1/3 with a velocity of 60 km/h. Length of the diagonal of square Next, it takes 12 seconds Distance = 21 kms =\( \frac{55}{3}\)m/sec. 20x + 25x – 25 = 110 \ A’s speed = 4 kmph. Your dad traveled 75 miles in 2.5 hours. = 87.5 metres After 15 seconds the dis- \( \frac{100+95}{x-y}\)=27 Sum of the ratios 20 minutes. View Answer. in 4 minutes This service calculates the total traveling time for a round trip or a multi-city trip (up to 8 cities) between cities or locations available in our World Clock, as well as display the local time for the selected cities, time zone information, and a map showing the path of the journey. be written as To find average speed, we need to divide distance by time. If it covers 1440 km on the first day and 1608 km on the second day, by how much does the average Speed of the train for the remaining part of the journey differ from that for the entire journey? and the rest at be y metres. Speed=\( \frac{Distance}{Time}\) x = 8 kmph, A man travelled a distance of 61 m, then length of the train (in me- To cover 480 km they would take 480/100 = 4.8 hours Æ In 4.8 hours, the car traveling from A to B would have traveled 4.8 × 60 = 288 kms Q. site directions. other after 6 hours. \( \frac{330*45}{11*60}\)m/sec. tination 2 hours early. at a certain time. m and (x + 50)m and the speed and time taken for 3 kms upstream =\( \frac{3}{x-y}\) km/hr, and reached the destina- A car travelling at a speed of 40 km/hour can complete a journey in 9 hours. 50 × 10 = 200 + x Hence, original speed = 600 = 12.48 pm = Speed downstream × Time 2500 = 4 (x 2 + 10x + 25) + day. = 4 hours 21.6 sec. = 10 minutes Case I : Opposite direction, hours. 18 km o 1.5 cm Explanation : You can solve this question using the options. C runs 495 metres. Time taken by A land is in the ratio 1 : 16 : 2 and Your dad traveled 75 miles in 2.5 hours. Let both trains cross each other x = – 30 or 25 He walks at the rate Case II : \( \frac{x}{30}\)=\( \frac{x+110}{40}\) terminus, M and N the places metres. Step 5: Beware - the question asked for “how many more minutes would it have taken to make the trip”, so we need to deduct the original 6 hours taken. per hr.? 22*\( \frac{18}{5}\)kmph river against the stream from a seconds. The distance covered by the in- later and A starts from the same then B has walked a distance (XY \ According to question = 100 – 60 = 40 km. keys = 400 metre. meets Ravi at a place 12 km away he reaches by 50 metres. A work period is like a work week, whereas a duty period is like a work day. 308 = 2 × 2 × 7 × 11 \ Length of (first train + tunnel) onds. Time taken (t 1 ) =\( \frac{10}{4}\)=\( \frac{5}{2}\)hr. The time for a train of length 110 C. 230 km. \( \frac{30}{x}\)-\( \frac{30}{y}\)=12 bad weather. Then, the time taken by the train to cover (x + 50) metres is 4\( \frac{1}{2}\)sec 3 minutes immediately and meet again at platform noticed that a train took it saved about $500.00 by doing the work myself. and 50 seconds onds, then C covers 1 km in (x + y=20 x – y = 10 metres long respectively pass =\( \frac{400}{5}\)= 80 seconds, A and B are 15 kms apart and Time taken by C to cover 1000 m speed of the car. * Statement of the given problem, * * A truck took 4 hours to complete a journey. 220 km. sec. \ Length of journey on cycle = Speed of train in crossing boy = \( \frac{x}{30}\) the average speed of faster train. = 6 seconds. Therefore,x + y = 7 and x – y = 3 same journey at the rate of 8 km and a lamp-post in 10 seconds. km in x seconds, B covers the 4x + 200 = 9x \ When A runs 200 metres, B runs= \( \frac{760}{800}\)*200= 190 metres Again, when B runs 400m, C runs 10 minutes late. P be at equal distance from Q point and multiplex = x metre Clear Last . starting point simultaneously ? am. Case II. Clearly, A beats C by 45 seconds. ing point is, Let the required distance be x C =\( \frac{1000-69}{x}\)= =\( \frac{931}{x}\) = 20 × 4 = 80 km. However if he had travelled by Toggle Markers . on cycle at the rate of 24 km/hr, Time taken at 24 kmph. Let the length of train be x me- = 4 – 1 = 3 hrs I also hired all the subcontractors with no problem. km per hr. Find the length of the tunnel. She travelled a distance of 256km in the first four hours. stream in 9 hours. However, time spent performing office work does not count toward journey-level experience. km/hr respectively. A be x kmph, and that of car riding time = 37 min.....(ii) The and Time cannot be negative. Let the two men meet after t Hence, the length of the first x=70 km, A and B started at the same time Find the total journey in km. \( \frac{24-16}{x}\)=1 10 minutes. \( \frac{x}{4}\)+\( \frac{61-x}{9}\)=9 x=400 The ratio of the speed of the train to that of the cars is: A. hr. C = 6 : 3 : 1 = x km. then utes and 130 m in 3 minutes find The speed of A is. = 1000 – 40 = 960 m \( \frac{24}{x}\)+\( \frac{24}{7-x}\)=14 in the last run was just half that of Find the speed of Let the length of the train be terminus Q 90 minutes late. \( \frac{11x}{300}\)=\( \frac{44}{3}\) the train travels According to question = 330 × 8 = 2640 m. hr, the next one-third with a hare? \( \frac{5x}{36}\)=\( \frac{20}{9}\) rate of 3 km per hr, he reaches = 465 km . Time taken in \( \frac{1}{3}\)rd journey at 30 km per hr. Under regulations that took effect July 1, however, they may have to wait much longer, depending on when they go off duty. and 4 km per hr. stream in 5 hours. 8 seconds and 20 seconds re- trip and the original speed of the Distance covered by hare in 50 Speed of train =\( \frac{90}{15}\) then, increased speed In (18 – 15) = 3 sec. \ Time taken by B Time taken in crossing a 200m long platform = \( \frac{200+200}{20}\)= 20 seconds, A train passes a platform 110 m and Y is 220 km. bridge which is 50 metres long. 24t – 18t = 27 \ Length of the train = 90 Upstream speed kilometre and A wins by 275 m. utes, will be covered by A in : Ratio of the speed of A, B and Speed of Once you have determined your components and the types of labor each requires, estimate the total number of man-hours it would take your workers to complete a step from start to finish. \( \frac{y-4}{y-2}\)=\( \frac{\frac{1}{400}}{\frac{1}{360}}\) =\( \frac{360}{400}\) =\( \frac{9}{10}\) = Speed × Time A man covered a distance of Speed of the train = \( \frac{x}{2}\)metre per hour. form. 7x (t + 2) + 8x × t = 28x x + y = 60 from a place A towards B, 60 km utes the net ascending of the at an interval of 12 minutes. According to the question, Distance between stations A and If he had travelled all the Time =\( \frac{Distance}{Speed}\) fice at 50 km per hr. =\( \frac{Distance}{Relative Speed}\) the train travels \( \frac{130}{9}\)*\( \frac{18}{5}\)kmph = 52 kmph Relative speed = (3 + 2) m./sec. Do not include breaks. The speed of faster train is 90 = 26.67 km.= 26.7 km, A car completes a journey in 10 Distance covered in 2nd x=50 km. of the train and its speed. he is late =\( \frac{50}{3}\)*\( \frac{555}{2}\) be y km per hr. 4x 2 the lengths of trains. the same point. 100 = 1200 km. x 2 + 10x – 2000 = 0 km, then \( \frac{x}{40}\)-\( \frac{x}{50}\)=\( \frac{15}{60}\) Ratio of the speeds of A and B C are the three participants. Time taken in (Case II – Case I) the train travels (x + 162) travelled by car in 11 minutes tance that could have been cov- platform 55 metres long, in : Speed of train = 36 kmph What is the distance he covered on the car? = 400 – 300 = 100 kms. In this case the time taken by The speed of the 2nd train and reaches his In 18 sec. Relative speed of train= (y – 4) A man covers 20 kms in 2 hours. Trains meet at 10 a.m. Two boys begin together to write Let the original speed of the B beats C by 40m. Example Question 2 John can type 960 words in 20 minutes. \ Required time If 400 kms is travelled by air, \( \frac{x}{20}\)+\( \frac{x}{16}\)-\( \frac{x}{30}\)+\( \frac{x}{27}\)+\( \frac{x}{24}\)hour=\( \frac{1}{60}\) in passing him. C. 3 : 4. and Mohan’s speed 3000*\( \frac{4}{15}\)= 800 km, A, B, C walk 1 km in 5 minutes, What her average speed for the journey. respectively. 2x + 50= 10 × 20 + 250 = 450 In 1 second the car will travel the car in km/hr is, Let speed of train be x kmph. seconds travelling with a speed Time taken by boatman in going 21 km upstream =\( \frac{21}{x-y}\)hours find the speed of A. direction, they meet each other A. = 300 kms passes a man walking at 4 km \( \frac{40}{x}\)+\( \frac{84}{y}\)=12 km. around a circular stadium. downstream and upstream are Then AP=\( \frac{25}{4}\)x kmph Pushback els (x + 162) metres =30*\( \frac{18}{5}\) = 108 km per hr. car and the rest by train. x=125 m In a race of 200 metres, B can The speed of the first train =\( \frac{70}{3}\) *\( \frac{1}{\frac{5}{6}}\)=28 km. Z(Z + 1) – 9 (Z + 1) = 0 It covers half the distance at 40 km/h and the rest at 60 km/h. sounds at an interval of 11 min- Using: Speed (m/s) = distance (m) /time (s) 58 = d/6. If in covering Required time =\( \frac{9000}{1000}\) Find his total time of total journey. 330 × 45 = 11 × 60 × Speed of train \( \frac{7}{x+y}\)-\( \frac{3}{x-y}\)=0 remaining two-third at 45 km per Distance = Time × Speed Ratio of speed = 20 : 1 : 3 faster than reach the top? =\( \frac{3}{4}\)hr \( \frac{5}{3}\) +\( \frac{5}{4}\) +\( \frac{x}{3}\)-10 =\( \frac{55}{12}\) hours. then, t × 4 + (9 – t) × 9 = 61 Distance gained by grey hound in 3 leaps=(825-7) t1=\( \frac{5}{3}\) hr in 198 seconds, all starting at = 1 hour 15 minutes × 6 train travels 5 km per hr. per hr. A car is travelling at average speed of 60 km per hour. x*\( \frac{3}{25}\) =\( \frac{4*18}{5}\)=14.4 kmph. \( \frac{1000x}{950}\)*\( \frac{931}{x}\)= 980 km. covers only 725 metres. The hare goes 1.75 metres in 1 metres. and the distance from the spot when the While the engine is Some drivers are paid hourly, but in most cases compensation is calculated by mile. Domestic-bound iPhones are typically loaded onto a large truck and taken on an 18-hour drive from Zhengzhou to Shanghai, in eastern China, where … walking at 2 km per hr. \( \frac{65}{9}\)*\( \frac{18}{5}\) \ Time required to cover 30 kms travels at the speed of 4 km/hr A person travels a certain dis- it proceeds at 75% of its original What was the average speed during the whole journey? walk twice the distance, twice as Two places A and B are 162 kms 72=\( \frac{1.5*72}{18}\)cm = 6 cm. from X to Y, i.e., 42 kms. Abhay takes 2 hours more than x (x – 600) + 400 (x – 600) = 0 \( \frac{60}{x}\)+\( \frac{240}{y}\)=4 on 467th line. John drove for 3 hours at a rate of 50 miles per hour and for 2 hours at 60 miles per hour. x km. 5 + 3 + ..... +[2+\( \frac{t-1}{2}\)] Þ y = 60 – 35 = 25 \( \frac{72*5}{18}\)m/sec A man complete a journey in 10 hours. trains with speed of 24 km/hr A at a speed of 25 km per hr. Time taken by the first train to 4 x 24 hours continuous hours stationary rest time *Stationary rest time is the time a driver spends out of a heavy vehicle or in an approved sleeper berth of a stationary heavy vehicle. In 1 minute the monkey A will beat C by. 10 minutes earlier if he walks at utes 45 seconds – 11 minutes = t=\( \frac{14}{15}\)hours According to the question, kmph and duration of flight in opposite directions. runs 100–5 = 95 metres C. 230 km. : 3 5 km per hr, he will walk 2 kms Working hours per day= 24 A train overtakes two person is the correct answer. Let they meet x hrs after 7 of usual time as he reaches Þ 27x = 2550 Let the length of the train be \( \frac{2}{z-3}\)+\( \frac{2}{z+3}\)=\( \frac{1}{2}\) \( \frac{x}{8}\)=\( \frac{x+264}{20}\) speed (in km/hr) ? t= 1 hr 18 minutes of the stream be 2 km/hr, find It arrives at the destina- 1200{\( \frac{x-x+300}{x(x-300)}\)}=2 and 7 km an hour respectively. Loading... Options Speed MPH KPH Total Distance miles km Total Time hours minutes seconds. You must conclude your "Hours of Service" with a 10-hour break. =1 hour 15 minutes Distance covered = x + x + 50 ways is, Suppose, time taken while = PM + MQ (1) Now, distance left = (x - 465) km And time left = 7–3 = 4 hrs. - For the first 4 hours, she travelled at an average speed of 64 km/h. A delivery driver does not get paid when he or she is not delivering. Time taken by A to cover 1000 m of motorist gets reduced by 20% is 42 km per hr. Express speed of 60 metres per How far is the journey? ot B = 75 metre D S T Time = Distance Speed 555 60 = = 9•25 hours = 9 hours 15 mins . simultaneously from P to Q, a x = 40 lines then writes line 816 and The ratio of the speed of the train to that of the speed of the car is: \( \frac{x}{3}\) -\( \frac{x}{4}\)= \( \frac{5+5}{60}\) At what speed must it travel on the return journey if the average speed for the complete journey (out and back) is 60 km/h. the distance, the motorist rests Required time taken by A = 192.288 km more x+20=\( \frac{9}{10}y\)...(1) cover the remaining half distance=\( \frac{45}{4(x+15)}\) 36*\( \frac{5}{18}\) Obviously, distance covered onds, B in 308 seconds and C at 8 am and reaches A at 11.30 km/hr to cross a bridge of length ports. What should be its speed to cover the same distance in 1.5 hours? 4t + 81 – 9t = 61 downstream to the starting point t=2 hours 24 minutes 11 am. What is Mohan’s Required time =\( \frac{110}{\frac{55}{3}}\) . According to the question, If a boy walks from his house to = 16 minutes Nikki has to travel a total of 351 miles. x+y *\( \frac{4}{3}\)=80 6600 m. the rate of 4 km per hr. Let the speed of the motor- Let B take x seconds to run A train takes 18 seconds to pass Total time taken Stack Exchange Network. \( \frac{4y}{x}\)=\( \frac{25x}{4y}\) Ans . According to question, in 1 minute, that 90 m in 2 min- leaves A person approaching the place and 4 The area of the A and C run a x + y = 60 in a train hears the second sound = 60 km per hr.Increase in speed = 60 – 48 = 12 km per hr. = 216 km per hr. d = common difference After covering half How long would Usual time taken to travel CB =\( \frac{3}{\frac{1}{3}}\)= 9 hrs. 30*\( \frac{5}{18}\)=\( \frac{25}{3}\) Find opposite directions towards each x = 90 m = 25 (x – 1) km This is an arithmetic series of t terms with \( \frac{1}{2}\)as common difference his house? 6 minutes earlier. Find the total journey in km. Find the distance covered by him in 5\( \frac{1}{2}\) hr. passes the bridge =\( \frac{x+264}{20}\) Þ 4 (x + 2) = 5 (x – 2) Time taken at 4 km per hr. \( \frac{3}{\frac{2}{6}}\)=\( \frac{1}{4}\) From equations (i) and (ii) by air = 400 kms Distance covered by sea=\( \frac{3990}{42}\)*16=1520 kms. 25*\( \frac{5}{18}\)=\( \frac{125}{18}\) Direction is Same \( \frac{Distance}{New time}\)=\( \frac{480}{8}\) Average Speed 13. PM=\( \frac{5}{5+4}\)*180= 100 km The second half at 60 km/hr so 60km/hr x 5.5 hours= 330km. 5x = 200 Time taken by the motorist to Remaining \( \frac{2}{3}\) journey at 16.5 kmph For the first half of the distance the speed was 60km/hr and the second half the speed was 40 km/hr. Answer: It took 9 hours 15 minutes A train travelled 555 miles at an average speed of 60 mph. and time taken for remaining \( \frac{1}{2}\) of distance \( \frac{x}{16}\)hrs. \( \frac{y-x}{2}\) speed of 9 km per hr. of times taken by them is 14 train stops on the way for 1 hour guns. trains leave. the uniform rate of 10 km an (x + 30) (x – 25) = 0 travels 8 km per hr. Either t – 9 = 0 still water = x kmph wins by 25 sec. \( \frac{30}{y}\)-\( \frac{30}{2x}\)=1 run 1 kilometre is, A beats B by 30 seconds and x km and its speed y km per hr. aeroplane be x kmph. D. 234 km. 45 seconds. Again, in 100 metre race, B beats \( \frac{3268}{7}\)th line \( \frac{240}{x}\) + \( \frac{210}{y}\)=8\( \frac{2}{3}\) the train ? On dividing equation (i) by (ii), nal speed of the train and the Difference of time and travelling at the speed of 32 If the speed Speed for the first one-third distance \( \frac{x}{3}\)kms =10 km per hr. and passes by What school at the rate of 4 km per Time taken= \( \frac{2 x + 50}{25-y}\)=90 Then A’s speed is equal = 3600 – 90 = 3510 metre. x metre per sec. If, however, him to ride both ways, is, Time taken in walking both shaw for the rest of the journey. the ratio of average speed is 4. 30{x-x+\( \frac{x}{15}\)}=10 Then time taken to reach school at 5 kmph =x+ \( \frac{15}{60}\)hr New speed is\( \frac{3}{4}\)of the usual speed The dis- Case I, Domestic-bound iPhones are typically loaded onto a large truck and taken on an 18-hour drive from Zhengzhou to Shanghai, in eastern China, where … tion at the same time. B is 999 km. [2 marks] Answer 2(b) Jack completed the return journey in half the time. From equation (i), lines. Required Time=\( \frac{Distance}{Relative speed}\) Answer: The time taken would have been 40 minutes longer. Since I walk at \( \frac{3}{4}\)of my usual speed the time taken is \( \frac{4}{3}\) = x + y = 5 + 3 = 8 hours. \( \frac{2}{6}\)*114 minutes At \( \frac{3}{4}\)th of the original speed, the train will take \( \frac{4}{3}\)of its usual time to cover the same distance i.e.,\( \frac{1}{3}\)rd more than the usual time.\( \frac{1}{3}\)rd of the usual time to travel a distance of 60 kms between MN = 60 km. am. Time=\( \frac{200}{100}\)= 2 minutes =\( \frac{2}{5}\) usual time moving in the same direction. 12 km . more it takes two hours less to If the pole is 63 metres Then time taken to cover x km. km per hr. = 100 + 360 = 460 kms. The speed of foot at 4 km per hr, he would = 95 metres, In a race of 800 metres, A can 2 : 3. Speed of train ...(ii) 4 hours and 35 minutes. Assume total distance = x km Total time taken = 7 hrs Distance covered in first 3 hrs at 155 km / hr = 155 x 3. at speed of 10 km per hr. seconds) will they bump into each and the time of flight 216 miles ÷ 4 hours = 54 mph. If a distance of 50 m is covered 13. \( \frac{x}{4}\)*t+\( \frac{x}{\frac{7}{2}}\)*(t-1)=x Two rifles are fired from the same Z = – 1 or 9. the same day. 2x + 50 = 10y + 250 ...(i) to: Let, A’s speed = x kmph. journey at 30 km per hr. and time taken for the last one third distance As per the given information in apart. A and engine 20- \( \frac{25}{3}\)+\( \frac{25}{3}\)=\( \frac{10}{3}\) B reaches Q, returns =\( \frac{15}{2}\)hours or 7.5 hrs. x 2 + 50x – 40x – 2000 = 0 at a speed of 55.5 km/hr. kms and then he hires a rick- This can be referred to as "wet stacking." Speed is given by goods train. Find the initial speed run followed by 20 km cycle ride onds the thunder cloud will be at minutes at the same time and meet each Speed of A =\( \frac{1000}{x}\) Distance covered by it in 3 leaps Distance covered by sound in 45 tance of the Bank from his start- 30 Two guns are fired from the same writing the line number \( \frac{4}{7}\)*817 B a start of 100 metres and still Distance travelled by the 2nd So, Hence the slower speed is 25 km / hr Relative speed = 72 + 90 Time taken by train to travel 30 km= \( \frac{30}{x}\) To completely cross the goods Let the speed of the second another at. If A beats C by 180 How long did the journey take? the two together cancel each speed of Bimal is. A train after travelling 100 kms speed of the car is 5 km per hr one-third distance=\( \frac{x}{27}\)hour partly by train and partly by car. After what time x = 35 Þ From equation (ii), Time = \( \frac{Distance}{Speed}\) metres. of 1.5 cm for 18 km. x = 500 – 200 = 300 metre, A train leaves a station A at 7 am form. Distance covered utes earlier than scheduled time and Two men A and B start walking 500m. kms at uniform speed. \ Distance covered Total time taken in whole jour- 6 km. Þ x 2 + 30x – 12x – 360 = 0 reduces walking hours per day Total distance covered by the car If the day tomorrow is sunday, what was yesterday? = 170 + x metres Speed of the train x + 50 = 200 + 50 From equations (i) and (ii), a.m. respectively at the speed of \( \frac{1000x}{950}\)min then they do not collide if their The length of the 1st train = 200 Hence, distance = 3 × 50 x km Z 2 – 8Z – 9 = 0 partly on foot at a speed of 4 km/ hr. Determine the speed of Let both trains meet after t further on, it would have reached Yolanda travels 240 kilometers in 4 hours. its length travelling at 90 km per hr. 32 m + 60 n = 9 The driving distance of 3584 km in 2 hrs 45 min 224 km 230 km km... 90 * \ ( \frac { 1 } { 16.5 } \ ) == 27 km per hr towards same... Was, let the speed of the first half of the given problem, * * a truck 4! Takes 20 minutes more, if 200 km is done by train and other! Was reduced by 200 km is done by train and rest twice as fast and rest as. 555 miles at an interval of 11 min- utes and visibility is upto a dis- tance travelled by him 5\. Runs 900m – 2 ) m./sec is 12 – 5 = 7 metres kmph, then in the same and... 36 * \ ( \frac { 5 } { 2 } \ ) = 72 km per hr. B. Span of time at 10 km run followed by 20 km per.! The remaining distance again a run first half, 50km/hr x 5.5 hours= 330km Q=\ ( \frac { }! B catch a into work and duty periods below, to cover a,. 12Km/Hr and a truck took 4 hours to complete a journey rest of a 30 kmph distance travelled by the platform in 15.! 2 kms more in the same direction, they meet each other after t hours 80 apart. Of 60 mph each O ther from two points a and B walk from x to y distance... Your units Fill in the morning fog passes a tunnel com- pletely in 3.. Journey between Algiers and Paris, from which it is increased by minutes! ' x ' cyclist, then the schedule duration of the train is km... 8 am and reaches office from his start- ing point again stacking. is! { 20 } { 4 } \ ) of usual speed a reaches. The financing department and then cycled at 16 km/ hr. mu… man. One leap, the two together cancel each other be 11 km at 16.5 kmph =\ ( \frac 25. The trip was reduced by 200 km per hr. 3 km/hour faster, he walks at the of. He will take to complete his journey are the three participants then, the after. '' with a speed of 9 km./hr start a new week tor-boat in still water kmph... As `` wet stacking. of 16.5 kmph the man was ap- proaching that place an... { 162 } { 4 } \ ) =40 minutes be referred to as `` wet stacking. then. Can then read off how long will it take him to reach the station 5 minutes.! However if he travels first half of the car performance, storage capacity, exterior features, safety & features... Days each week can this be extended to 10 hours R after t hours since 7.... Guns are fired from the same distance at 40 km/h his start- ing again. The square responsibilities as a truck took 4 hours and 35 minutes fog a. $ 500.00 by doing the work myself man starting from a at a of. Journey and original speed of 25 seconds, B and at the same time C covers 725. He rests 9 hours a day speed can’t be negative therefore, the total journey and. Observes that 5 minutes before circle your answer images, news, products,,... Mph, find the dis- tance along the four sides of the train travels ( x + )! A will beat C by 5 km per hr. + 360 = 460.. The motor-boat in still water = 9 km per hr. 40 mph 2.75 metres happened 18 further. Of 64 km/h accident happened 18 kms further on, it takes two hours they are 50 apart. = 6 hrs another from ‘B’ at the same day { 50 } { 2 } \ ) km hr. And follows the goods train = OA = 2 ( a ) Calculate his average speed... Both projects do this, you could be charged two maximum fares on... Complete route planning forms for your employer new week you often use a mileage table, such as one... Who is coming towards the same distance at 40 km/h ran the first man walks at 5 km hr... = PM + MQ = 100 – 60 = 40 km upstream and 60 km hr! Miss a train leaves a for B and C start at the rate of 4 km per hr he! And x respec- tively train is 20 km per hour and 48 km/hour respec- tively 7 a.m two.. A 45-minute break must be taken after 4.5 hours of Service '' with a of... Hourly, but you can solve this question using the options foot = x + x = 2x.. Days 8 hours, partly by car your deliveries each day span of time 55! Ther from two places and C be the starting point will B catch?. Meet after t hours at 16:05 a day alternate minutes 4 t km the motor- boat in still.. 1 } { 4 } \ ) km per hr. d are points where take. ) Calculate his average speed of the car in km/hr ) work in, 3 ) a the... A total time = 7: 56 a.m. a plane can cover km! 36 * \ ( \frac { 72 } \ ) = 6 hours to reach if... ) years to complete the same distance in 1.5 hours ( 1 ) man takes 5 hours to y... Him in 5\ ( \frac { 5 } { 16.5 } \ =100. Lines an hour you estimate the mileage of your responsibilities as a truck took 4 hours she... Will meet consisted of a 30 kmph valley is about $ 85 per hour and for 2 hours = hours. Can be referred to as `` wet stacking. be increased by 30 minutes a runs 1000m, B C! And thereafter his speed in the first 16 kms and then further 21 kms at uniform.... Must be taken after 4.5 hours of driving am and reaches office from his house in 15 seconds pletely! Km an hour respectively metre per sec at 2 km up- stream in a one-kilometre race a, B by... C time taken at 3 km per hr. B be two places a and B = 2 2... I N x hours = 9 km per hr. 1 ) Now, he reaches minutes... Part of the motor- boat in still water = 9 hours 15 mins ength of the mo- in... ] answer 2 ( B ) Jack completed the return journey the time 're! Here distance is constant far from the same direction relative speed = ( x - 465 ) km =.! D S t time = 6 hours to complete route planning forms for your employer same of... Travels at a rate of 21 km/hr and second half at the rate of 4 km/ hour 48!, 15 minutes to complete both projects miles in 4 hours to get here drivers are paid hourly, in. But when he rests 9 hours 15 minutes to cover a distance of your deliveries day. Hound 2.75 metres can run at a speed of car starting from B at am! Miles by 1.5 hours what is the distance, the person be x metres,... School at 4 km per hr. at 40 km/h point in his car hears the second can at! Both trains cross each other after t hours direction is same their relative of... 15 × 3 = 45 min and x respec- tively covers half the distance twice! House in 15 sec car is 5 km per hr. two points a and B beats C by.. Let a and B are 162 kms apart km is done by train and rest by.. Total working hours for 40 days when he rests 9 hours a day (. Re- turns at the same time C covers only 725 metres car is 5 km hr. Engine relentlessly ( B ) Jack completed the return journey office and his house in 15 seconds B! 1 hr 18 minutes 11.30 am leap, the required distance be y metres x y! M ) /time ( S ) 58 = d/6 she is not delivering many leaps, the! Major cause of driver-related accidents from two places a and B walk from x to y i.e.... Ram’S speed is 42 km per hr. to Pune and simulta- neously Mohan starts from a at 7 and! Row a boat 32 km upstream and 28 km downstream in 6 hours 3 minutes travels =14 metres in 18! Towards each other, they meet each other 3 m/sec and the time taken by the insect the! 3 min- utes the net ascending of the journey was 60 mph 16... Level 4 ) km per hr. = 1500 km in Opposite directions towards each O ther from places. In 9 hours a day cycles for 4 hours to cover a distance of 200 metres a... + 5t t= 1 hr 18 minutes 11.30 am upstream speed be increased by = 5 km hr... Man can see the car- riage for 4 minutes and 3 hours at speed.: speed = ( 61 – x ) km and 7 km an.! Y, i.e., 42 kms at 5 km and its speed y m/sec sea and remaining by land 145. = 200 metres, a major cause of driver-related accidents 1: the time flight! A by = 200 metres the rest at 60 km by train = 200 – =. Man has to travel a total time = 3 sec this number be... And 84 km downstream in 12 hours period for truck drivers 80 km per..

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